What are the solutions to the equation -3x^2=4 ?

The solutions to the equation -3x^2=4 are x= 2/(sqrt(3))i,x=-2/(sqrt(3))i

Find the zeros of -3x^2=4

The zeros of -3x^2=4 are x= 2/(sqrt(3))i,x=-2/(sqrt(3))i

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- 3 x^{2} = 4

x = \frac{2}{3} i, x = - \frac{2}{3} i

Solution steps

- 3 x^{2} = 4

Divide both sides by

- 3

x^{2} = - \frac{4}{3}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - \frac{4}{3}, x = - - \frac{4}{3}

- \frac{4}{3} = \frac{2}{3} i

- - \frac{4}{3} = - \frac{2}{3} i

x = \frac{2}{3} i, x = - \frac{2}{3} i

v^{2} + 4 v - 17 = v

4 x - 1 = x^{2}

x^{2} + 2 x = 0

2 x^{2} - 16 x + 38

m, 6 m^{2} - 8 m + 1 = 0

What are the solutions to the equation -3x^2=4 ?
The solutions to the equation -3x^2=4 are x= 2/(sqrt(3))i,x=-2/(sqrt(3))i
Find the zeros of -3x^2=4
The zeros of -3x^2=4 are x= 2/(sqrt(3))i,x=-2/(sqrt(3))i