What are the solutions to the equation 30+27x=400-x^2 ?

The solutions to the equation 30+27x=400-x^2 are x=-37,x=10

Find the zeros of 30+27x=400-x^2

The zeros of 30+27x=400-x^2 are x=-37,x=10

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30 + 27 x = 400 - x^{2}

x = - 37, x = 10

Solution steps

30 + 27 x = 400 - x^{2}

Switch sides

400 - x^{2} = 30 + 27 x

Move

27 x

to the left side

400 - x^{2} - 27 x = 30

Move

30

to the left side

- x^{2} - 27 x + 370 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 27 ) \pm ( - 27 ) ^{2} - 4 ( - 1 ) \cdot 370}{2 ( - 1 )}

(- 27)^{2} - 4 (- 1) \cdot 370 = 47

x_{1, 2} = \frac{- ( - 27 ) \pm 47}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- ( - 27 ) + 47}{2 ( - 1 )}, x_{2} = \frac{- ( - 27 ) - 47}{2 ( - 1 )}

x = \frac{- ( - 27 ) + 47}{2 ( - 1 )} : - 37

x = \frac{- ( - 27 ) - 47}{2 ( - 1 )} : 10

The solutions to the quadratic equation are:

x = - 37, x = 10

y, 4 x^{2} + 5 x y + y^{2} + 3 x - 2 y - 7 = 0

x, t (x) = - 2 x + \frac{1}{3} x^{2}

x^{2} + 3

(2 x - 1)^{2} = 75

2 x^{2} + 8 x + 30 = 5

What are the solutions to the equation 30+27x=400-x^2 ?
The solutions to the equation 30+27x=400-x^2 are x=-37,x=10
Find the zeros of 30+27x=400-x^2
The zeros of 30+27x=400-x^2 are x=-37,x=10