What are the solutions to the equation 4m^2-5m-3=2m ?

The solutions to the equation 4m^2-5m-3=2m are m=(7+sqrt(97))/8 ,m=(7-sqrt(97))/8

Find the zeros of 4m^2-5m-3=2m

The zeros of 4m^2-5m-3=2m are m=(7+sqrt(97))/8 ,m=(7-sqrt(97))/8

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4 m^{2} - 5 m - 3 = 2 m

m = \frac{7 + 97}{8}, m = \frac{7 - 97}{8}

Decimal Notation

m = 2.10610 \dots, m = - 0.35610 \dots

Solution steps

4 m^{2} - 5 m - 3 = 2 m

Move

2 m

to the left side

4 m^{2} - 7 m - 3 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 4 ( - 3 )}{2 \cdot 4}

(- 7)^{2} - 4 \cdot 4 (- 3) = 97

m_{1, 2} = \frac{- ( - 7 ) \pm 97}{2 \cdot 4}

Separate the solutions

m_{1} = \frac{- ( - 7 ) + 97}{2 \cdot 4}, m_{2} = \frac{- ( - 7 ) - 97}{2 \cdot 4}

m = \frac{- ( - 7 ) + 97}{2 \cdot 4} : \frac{7 + 97}{8}

m = \frac{- ( - 7 ) - 97}{2 \cdot 4} : \frac{7 - 97}{8}

The solutions to the quadratic equation are:

m = \frac{7 + 97}{8}, m = \frac{7 - 97}{8}

x^{2} - 9 x + 3 = 3

x^{2} + 27 = - 11 x + 3

y, x^{2} y - x y^{2} + x^{2} + y^{2} = 0

8 x^{2} - 19 x + 6 = 0

4 - 2 x^{2} = - 14

What are the solutions to the equation 4m^2-5m-3=2m ?
The solutions to the equation 4m^2-5m-3=2m are m=(7+sqrt(97))/8 ,m=(7-sqrt(97))/8
Find the zeros of 4m^2-5m-3=2m
The zeros of 4m^2-5m-3=2m are m=(7+sqrt(97))/8 ,m=(7-sqrt(97))/8