What are the solutions to the equation roots x^2-bx+15 ?

The solutions to the equation roots x^2-bx+15 are x=(b+sqrt(b^2-60))/2 ,x=(b-sqrt(b^2-60))/2

Find the zeros of roots x^2-bx+15

The zeros of roots x^2-bx+15 are x=(b+sqrt(b^2-60))/2 ,x=(b-sqrt(b^2-60))/2

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roots

x^{2} - b x + 15

x = \frac{b + b ^{2} - 60}{2}, x = \frac{b - b ^{2} - 60}{2}

Solution steps

x^{2} - b x + 15

The roots are the intercepts with the x-axis

(y = 0)

x^{2} - b x + 15 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - b ) \pm ( - b ) ^{2} - 4 \cdot 1 \cdot 15}{2 \cdot 1}

Simplify

(- b)^{2} - 4 \cdot 1 \cdot 15 : b^{2} - 60

x_{1, 2} = \frac{- ( - b ) \pm b ^{2} - 60}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - b ) + b ^{2} - 60}{2 \cdot 1}, x_{2} = \frac{- ( - b ) - b ^{2} - 60}{2 \cdot 1}

x = \frac{- ( - b ) + b ^{2} - 60}{2 \cdot 1} : \frac{b + b ^{2} - 60}{2}

x = \frac{- ( - b ) - b ^{2} - 60}{2 \cdot 1} : \frac{b - b ^{2} - 60}{2}

The solutions to the quadratic equation are:

x = \frac{b + b ^{2} - 60}{2}, x = \frac{b - b ^{2} - 60}{2}

500 S^{2} + 60 S + 1 = 0

3 r^{2} = 12 r

n (n + 1) = 182

y, 3 x^{2} + 2 x y + y^{2} = 1

x^{2} = 13 x - 44

What are the solutions to the equation roots x^2-bx+15 ?
The solutions to the equation roots x^2-bx+15 are x=(b+sqrt(b^2-60))/2 ,x=(b-sqrt(b^2-60))/2
Find the zeros of roots x^2-bx+15
The zeros of roots x^2-bx+15 are x=(b+sqrt(b^2-60))/2 ,x=(b-sqrt(b^2-60))/2