What are the solutions to the equation n^2+225n-2835000=0 ?

The solutions to the equation n^2+225n-2835000=0 are n=1575,n=-1800

Find the zeros of n^2+225n-2835000=0

The zeros of n^2+225n-2835000=0 are n=1575,n=-1800

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n^{2} + 225 n - 2835000 = 0

n = 1575, n = - 1800

Solution steps

n^{2} + 225 n - 2835000 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- 225 \pm 22 5 ^{2} - 4 \cdot 1 \cdot ( - 2835000 )}{2 \cdot 1}

22 5^{2} - 4 \cdot 1 \cdot (- 2835000) = 3375

n_{1, 2} = \frac{- 225 \pm 3375}{2 \cdot 1}

Separate the solutions

n_{1} = \frac{- 225 + 3375}{2 \cdot 1}, n_{2} = \frac{- 225 - 3375}{2 \cdot 1}

n = \frac{- 225 + 3375}{2 \cdot 1} : 1575

n = \frac{- 225 - 3375}{2 \cdot 1} : - 1800

The solutions to the quadratic equation are:

n = 1575, n = - 1800

3 x^{2} + 5 x = 35

0.39 x^{2} - 52.81 x + 50.142 = 0

- x^{2} + 29 x + 342 = 0

3 k^{2} - 3 k - 126 = 0

13 + 3 x^{2} = 16

What are the solutions to the equation n^2+225n-2835000=0 ?
The solutions to the equation n^2+225n-2835000=0 are n=1575,n=-1800
Find the zeros of n^2+225n-2835000=0
The zeros of n^2+225n-2835000=0 are n=1575,n=-1800