What are the solutions to the equation completesquare 8x^2+16x=42 ?

The solutions to the equation completesquare 8x^2+16x=42 are x= 3/2 ,x=-7/2

Find the zeros of completesquare 8x^2+16x=42

The zeros of completesquare 8x^2+16x=42 are x= 3/2 ,x=-7/2

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8 x^{2} + 16 x = 42

x = \frac{3}{2}, x = - \frac{7}{2}

Decimal Notation

x = 1.5, x = - 3.5

Solution steps

8 x^{2} + 16 x = 42

Divide both sides by

8

\frac{8 x ^{2} + 16 x}{8} = \frac{42}{8}

x^{2} + 2 x = \frac{21}{4}

Rewrite in the form

(x + a)^{2} = b

(x + 1)^{2} = \frac{25}{4}

For

the solutions are

f (x) = a, - a

Solve

x + 1 = \frac{25}{4} : x = \frac{3}{2}

Solve

x + 1 = - \frac{25}{4} : x = - \frac{7}{2}

The solutions to the quadratic equation are:

x = \frac{3}{2}, x = - \frac{7}{2}

3 x^{2} + 18 x + 21 = 0

81 = π r^{2}

- 2 x^{2} + 4 x - 20 = 0

x^{2} = 8 x + 1

12 x^{2} - 17 x - 40 = 0

What are the solutions to the equation completesquare 8x^2+16x=42 ?
The solutions to the equation completesquare 8x^2+16x=42 are x= 3/2 ,x=-7/2
Find the zeros of completesquare 8x^2+16x=42
The zeros of completesquare 8x^2+16x=42 are x= 3/2 ,x=-7/2