What are the solutions to the equation roots s^2+8s+25 ?

The solutions to the equation roots s^2+8s+25 are s=-4+3i,s=-4-3i

Find the zeros of roots s^2+8s+25

The zeros of roots s^2+8s+25 are s=-4+3i,s=-4-3i

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roots

s^{2} + 8 s + 25

s = - 4 + 3 i, s = - 4 - 3 i

Solution steps

s^{2} + 8 s + 25

The roots are the intercepts with the x-axis

(y = 0)

s^{2} + 8 s + 25 = 0

Solve with the quadratic formula

s_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot 25}{2 \cdot 1}

Simplify

8^{2} - 4 \cdot 1 \cdot 25 : 6 i

s_{1, 2} = \frac{- 8 \pm 6 i}{2 \cdot 1}

Separate the solutions

s_{1} = \frac{- 8 + 6 i}{2 \cdot 1}, s_{2} = \frac{- 8 - 6 i}{2 \cdot 1}

s = \frac{- 8 + 6 i}{2 \cdot 1} : - 4 + 3 i

s = \frac{- 8 - 6 i}{2 \cdot 1} : - 4 - 3 i

The solutions to the quadratic equation are:

s = - 4 + 3 i, s = - 4 - 3 i

s^{2} - 4 s + 8

4 x^{2} = - 64

(13 x - 11) (13 x - 15) = 330

x^{2} - 6 x + 7 = 4 x

24 t^{2} - 216 t + 480 = 0

What are the solutions to the equation roots s^2+8s+25 ?
The solutions to the equation roots s^2+8s+25 are s=-4+3i,s=-4-3i
Find the zeros of roots s^2+8s+25
The zeros of roots s^2+8s+25 are s=-4+3i,s=-4-3i