What are the solutions to the equation 5/4 x^2+7x+9=0 ?

The solutions to the equation 5/4 x^2+7x+9=0 are x=-2,x=-18/5

Find the zeros of 5/4 x^2+7x+9=0

The zeros of 5/4 x^2+7x+9=0 are x=-2,x=-18/5

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\frac{5}{4} x^{2} + 7 x + 9 = 0

x = - 2, x = - \frac{18}{5}

Decimal Notation

x = - 2, x = - 3.6

Solution steps

\frac{5}{4} x^{2} + 7 x + 9 = 0

Multiply both sides by

4

5 x^{2} + 28 x + 36 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 28 \pm 2 8 ^{2} - 4 \cdot 5 \cdot 36}{2 \cdot 5}

2 8^{2} - 4 \cdot 5 \cdot 36 = 8

x_{1, 2} = \frac{- 28 \pm 8}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 28 + 8}{2 \cdot 5}, x_{2} = \frac{- 28 - 8}{2 \cdot 5}

x = \frac{- 28 + 8}{2 \cdot 5} : - 2

x = \frac{- 28 - 8}{2 \cdot 5} : - \frac{18}{5}

The solutions to the quadratic equation are:

x = - 2, x = - \frac{18}{5}

y, y x^{2} - 4 y - x^{2} = 0

n (x) = - x^{2} + 8 x - 9

(x + 8) (4 x + 1) = 0

y, x = a - 2 b y^{2}

x^{2} - 4 x - 3

What are the solutions to the equation 5/4 x^2+7x+9=0 ?
The solutions to the equation 5/4 x^2+7x+9=0 are x=-2,x=-18/5
Find the zeros of 5/4 x^2+7x+9=0
The zeros of 5/4 x^2+7x+9=0 are x=-2,x=-18/5