What are the solutions to the equation 2x^2-15x-100=0 ?

The solutions to the equation 2x^2-15x-100=0 are x=(15+5sqrt(41))/4 ,x=(15-5sqrt(41))/4

Find the zeros of 2x^2-15x-100=0

The zeros of 2x^2-15x-100=0 are x=(15+5sqrt(41))/4 ,x=(15-5sqrt(41))/4

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2 x^{2} - 15 x - 100 = 0

x = \frac{15 + 5 41}{4}, x = \frac{15 - 5 41}{4}

Decimal Notation

x = 11.75390 \dots, x = - 4.25390 \dots

Solution steps

2 x^{2} - 15 x - 100 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 15 ) \pm ( - 15 ) ^{2} - 4 \cdot 2 ( - 100 )}{2 \cdot 2}

(- 15)^{2} - 4 \cdot 2 (- 100) = 541

x_{1, 2} = \frac{- ( - 15 ) \pm 5 41}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 15 ) + 5 41}{2 \cdot 2}, x_{2} = \frac{- ( - 15 ) - 5 41}{2 \cdot 2}

x = \frac{- ( - 15 ) + 5 41}{2 \cdot 2} : \frac{15 + 5 41}{4}

x = \frac{- ( - 15 ) - 5 41}{2 \cdot 2} : \frac{15 - 5 41}{4}

The solutions to the quadratic equation are:

x = \frac{15 + 5 41}{4}, x = \frac{15 - 5 41}{4}

x^{3} - 2 x^{2} - 7 x + 2

3 x^{2} + 14 x - 5

12 x^{4} - 9 x^{2}

7 (- 5) - 2 (0) = 13

What are the solutions to the equation 2x^2-15x-100=0 ?
The solutions to the equation 2x^2-15x-100=0 are x=(15+5sqrt(41))/4 ,x=(15-5sqrt(41))/4
Find the zeros of 2x^2-15x-100=0
The zeros of 2x^2-15x-100=0 are x=(15+5sqrt(41))/4 ,x=(15-5sqrt(41))/4