What are the solutions to the equation (6x-3)(-x+3)=0 ?

The solutions to the equation (6x-3)(-x+3)=0 are x= 1/2 ,x=3

Find the zeros of (6x-3)(-x+3)=0

The zeros of (6x-3)(-x+3)=0 are x= 1/2 ,x=3

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(6 x - 3) (- x + 3) = 0

x = \frac{1}{2}, x = 3

Decimal Notation

x = 0.5, x = 3

Solution steps

(6 x - 3) (- x + 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

6 x - 3 = 0 or - x + 3 = 0

Solve

6 x - 3 = 0 : x = \frac{1}{2}

Solve

- x + 3 = 0 : x = 3

The solutions to the quadratic equation are:

x = \frac{1}{2}, x = 3

0 = 4 + 23.5 t - 4.9 t^{2}

3 y^{2} - 4 y = 2 y + 7 y

- 33.2 x^{2} - 2.66 x + 0.04 = 0

y, 2 x^{2} + 3 y^{2} - 8 x + 6 y + 14 = 0

F, g b + N b = 2 F (b)^{2}

What are the solutions to the equation (6x-3)(-x+3)=0 ?
The solutions to the equation (6x-3)(-x+3)=0 are x= 1/2 ,x=3
Find the zeros of (6x-3)(-x+3)=0
The zeros of (6x-3)(-x+3)=0 are x= 1/2 ,x=3