What are the solutions to the equation -5x^2+4x-6=0 ?

The solutions to the equation -5x^2+4x-6=0 are x= 2/5-i(sqrt(26))/5 ,x= 2/5+i(sqrt(26))/5

Find the zeros of -5x^2+4x-6=0

The zeros of -5x^2+4x-6=0 are x= 2/5-i(sqrt(26))/5 ,x= 2/5+i(sqrt(26))/5

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- 5 x^{2} + 4 x - 6 = 0

x = \frac{2}{5} - i \frac{26}{5}, x = \frac{2}{5} + i \frac{26}{5}

Solution steps

- 5 x^{2} + 4 x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 ( - 5 ) ( - 6 )}{2 ( - 5 )}

Simplify

4^{2} - 4 (- 5) (- 6) : 226 i

x_{1, 2} = \frac{- 4 \pm 2 26 i}{2 ( - 5 )}

Separate the solutions

x_{1} = \frac{- 4 + 2 26 i}{2 ( - 5 )}, x_{2} = \frac{- 4 - 2 26 i}{2 ( - 5 )}

x = \frac{- 4 + 2 26 i}{2 ( - 5 )} : \frac{2}{5} - i \frac{26}{5}

x = \frac{- 4 - 2 26 i}{2 ( - 5 )} : \frac{2}{5} + i \frac{26}{5}

The solutions to the quadratic equation are:

x = \frac{2}{5} - i \frac{26}{5}, x = \frac{2}{5} + i \frac{26}{5}

x, x^{2} + y^{2} + z^{2} = 4 z

x^{2} - 2 x + 1 = 0

r^{2} = - 4

25 x^{2} + 40 x - 9 = 0

x^{2} - 36 = 12 x

What are the solutions to the equation -5x^2+4x-6=0 ?
The solutions to the equation -5x^2+4x-6=0 are x= 2/5-i(sqrt(26))/5 ,x= 2/5+i(sqrt(26))/5
Find the zeros of -5x^2+4x-6=0
The zeros of -5x^2+4x-6=0 are x= 2/5-i(sqrt(26))/5 ,x= 2/5+i(sqrt(26))/5