What are the solutions to the equation factor 2x^2+3x-2=0 ?

The solutions to the equation factor 2x^2+3x-2=0 are x= 1/2 ,x=-2

Find the zeros of factor 2x^2+3x-2=0

The zeros of factor 2x^2+3x-2=0 are x= 1/2 ,x=-2

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2 x^{2} + 3 x - 2 = 0

x = \frac{1}{2}, x = - 2

Decimal Notation

x = 0.5, x = - 2

Solution steps

2 x^{2} + 3 x - 2 = 0

Factor

2 x^{2} + 3 x - 2 : (2 x - 1) (x + 2)

(2 x - 1) (x + 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

2 x - 1 = 0 or x + 2 = 0

Solve

2 x - 1 = 0 : x = \frac{1}{2}

Solve

x + 2 = 0 : x = - 2

The solutions to the quadratic equation are:

x = \frac{1}{2}, x = - 2

x^{2} - 5 x = 8

y, x^{2} + y^{2} = \frac{2 y}{x}

- 3 x^{2} + 12 x - 4 = - 12

5 a^{2} = 320

4 x^{2} + 1 = 8 x - 2

What are the solutions to the equation factor 2x^2+3x-2=0 ?
The solutions to the equation factor 2x^2+3x-2=0 are x= 1/2 ,x=-2
Find the zeros of factor 2x^2+3x-2=0
The zeros of factor 2x^2+3x-2=0 are x= 1/2 ,x=-2