What are the solutions to the equation roots x^2+4x+6 ?

The solutions to the equation roots x^2+4x+6 are x=-2+sqrt(2)i,x=-2-sqrt(2)i

Find the zeros of roots x^2+4x+6

The zeros of roots x^2+4x+6 are x=-2+sqrt(2)i,x=-2-sqrt(2)i

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roots

x^{2} + 4 x + 6

x = - 2 + 2 i, x = - 2 - 2 i

Solution steps

x^{2} + 4 x + 6

The roots are the intercepts with the x-axis

(y = 0)

x^{2} + 4 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot 6}{2 \cdot 1}

Simplify

4^{2} - 4 \cdot 1 \cdot 6 : 22 i

x_{1, 2} = \frac{- 4 \pm 2 2 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 4 + 2 2 i}{2 \cdot 1}, x_{2} = \frac{- 4 - 2 2 i}{2 \cdot 1}

x = \frac{- 4 + 2 2 i}{2 \cdot 1} : - 2 + 2 i

x = \frac{- 4 - 2 2 i}{2 \cdot 1} : - 2 - 2 i

The solutions to the quadratic equation are:

x = - 2 + 2 i, x = - 2 - 2 i

n, s = \frac{n ( n + 1 )}{2}

4 x^{2} + 45 = - 20 x

x^{2} = 3 x - 11

z^{2} + 0.4 z + 0.13 = 0

20 x^{2} = 18 - 37 x

What are the solutions to the equation roots x^2+4x+6 ?
The solutions to the equation roots x^2+4x+6 are x=-2+sqrt(2)i,x=-2-sqrt(2)i
Find the zeros of roots x^2+4x+6
The zeros of roots x^2+4x+6 are x=-2+sqrt(2)i,x=-2-sqrt(2)i