What are the solutions to the equation 2x^2+13x+11=0 ?

The solutions to the equation 2x^2+13x+11=0 are x=-1,x=-11/2

Find the zeros of 2x^2+13x+11=0

The zeros of 2x^2+13x+11=0 are x=-1,x=-11/2

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2 x^{2} + 13 x + 11 = 0

x = - 1, x = - \frac{11}{2}

Decimal Notation

x = - 1, x = - 5.5

Solution steps

2 x^{2} + 13 x + 11 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 13 \pm 1 3 ^{2} - 4 \cdot 2 \cdot 11}{2 \cdot 2}

1 3^{2} - 4 \cdot 2 \cdot 11 = 9

x_{1, 2} = \frac{- 13 \pm 9}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 13 + 9}{2 \cdot 2}, x_{2} = \frac{- 13 - 9}{2 \cdot 2}

x = \frac{- 13 + 9}{2 \cdot 2} : - 1

x = \frac{- 13 - 9}{2 \cdot 2} : - \frac{11}{2}

The solutions to the quadratic equation are:

x = - 1, x = - \frac{11}{2}

4 y^{2} + 12 y - 40 = 0

2 (3 x - 4) x - 1 = - 16

15 + 4 x - x^{2}

12 x^{2} + 6 a x + 2 b = 0

- 5 x^{2} - 80 x - 330 = 0

What are the solutions to the equation 2x^2+13x+11=0 ?
The solutions to the equation 2x^2+13x+11=0 are x=-1,x=-11/2
Find the zeros of 2x^2+13x+11=0
The zeros of 2x^2+13x+11=0 are x=-1,x=-11/2