What are the solutions to the equation 4x^2-8x=0 ?

The solutions to the equation 4x^2-8x=0 are x=2,x=0

Find the zeros of 4x^2-8x=0

The zeros of 4x^2-8x=0 are x=2,x=0

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4 x^{2} - 8 x = 0

x = 2, x = 0

Solution steps

4 x^{2} - 8 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 4 \cdot 0}{2 \cdot 4}

(- 8)^{2} - 4 \cdot 4 \cdot 0 = 8

x_{1, 2} = \frac{- ( - 8 ) \pm 8}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 8}{2 \cdot 4}, x_{2} = \frac{- ( - 8 ) - 8}{2 \cdot 4}

x = \frac{- ( - 8 ) + 8}{2 \cdot 4} : 2

x = \frac{- ( - 8 ) - 8}{2 \cdot 4} : 0

The solutions to the quadratic equation are:

x = 2, x = 0

20!

4 n^{2} + 12 n + 8

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What are the solutions to the equation 4x^2-8x=0 ?
The solutions to the equation 4x^2-8x=0 are x=2,x=0
Find the zeros of 4x^2-8x=0
The zeros of 4x^2-8x=0 are x=2,x=0