What are the solutions to the equation 12x^2-312x+1512=0 ?

The solutions to the equation 12x^2-312x+1512=0 are x=13+sqrt(43),x=13-sqrt(43)

Find the zeros of 12x^2-312x+1512=0

The zeros of 12x^2-312x+1512=0 are x=13+sqrt(43),x=13-sqrt(43)

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12 x^{2} - 312 x + 1512 = 0

x = 13 + 43, x = 13 - 43

Decimal Notation

x = 19.55743 \dots, x = 6.44256 \dots

Solution steps

12 x^{2} - 312 x + 1512 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 312 ) \pm ( - 312 ) ^{2} - 4 \cdot 12 \cdot 1512}{2 \cdot 12}

(- 312)^{2} - 4 \cdot 12 \cdot 1512 = 2443

x_{1, 2} = \frac{- ( - 312 ) \pm 24 43}{2 \cdot 12}

Separate the solutions

x_{1} = \frac{- ( - 312 ) + 24 43}{2 \cdot 12}, x_{2} = \frac{- ( - 312 ) - 24 43}{2 \cdot 12}

x = \frac{- ( - 312 ) + 24 43}{2 \cdot 12} : 13 + 43

x = \frac{- ( - 312 ) - 24 43}{2 \cdot 12} : 13 - 43

The solutions to the quadratic equation are:

x = 13 + 43, x = 13 - 43

x, 4 x^{2} + 6 y^{2} - z^{2} = - 5

(x + 5) (x + 8) = 180

4 x^{2} - 2.90827 x + 0.528679 = 0

2 x^{2} + 14 = 70

2 x^{2} + x - 6 = 0

What are the solutions to the equation 12x^2-312x+1512=0 ?
The solutions to the equation 12x^2-312x+1512=0 are x=13+sqrt(43),x=13-sqrt(43)
Find the zeros of 12x^2-312x+1512=0
The zeros of 12x^2-312x+1512=0 are x=13+sqrt(43),x=13-sqrt(43)