What are the solutions to the equation (2x-3)(x+6)=8 ?

The solutions to the equation (2x-3)(x+6)=8 are x=2,x=-13/2

Find the zeros of (2x-3)(x+6)=8

The zeros of (2x-3)(x+6)=8 are x=2,x=-13/2

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(2 x - 3) (x + 6) = 8

x = 2, x = - \frac{13}{2}

Decimal Notation

x = 2, x = - 6.5

Solution steps

(2 x - 3) (x + 6) = 8

Expand

(2 x - 3) (x + 6) : 2 x^{2} + 9 x - 18

2 x^{2} + 9 x - 18 = 8

Move

8

to the left side

2 x^{2} + 9 x - 26 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 2 ( - 26 )}{2 \cdot 2}

9^{2} - 4 \cdot 2 (- 26) = 17

x_{1, 2} = \frac{- 9 \pm 17}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 9 + 17}{2 \cdot 2}, x_{2} = \frac{- 9 - 17}{2 \cdot 2}

x = \frac{- 9 + 17}{2 \cdot 2} : 2

x = \frac{- 9 - 17}{2 \cdot 2} : - \frac{13}{2}

The solutions to the quadratic equation are:

x = 2, x = - \frac{13}{2}

2 x^{2} + 32 x + 126 = 0

x^{2} + 27 x - 160 = 0

6 t^{2} + 12 t - 210 = 0

t, 6 (2 t - 1)^{2} = 0

4 (x + 6) + 4 x = x (x + 6)

What are the solutions to the equation (2x-3)(x+6)=8 ?
The solutions to the equation (2x-3)(x+6)=8 are x=2,x=-13/2
Find the zeros of (2x-3)(x+6)=8
The zeros of (2x-3)(x+6)=8 are x=2,x=-13/2