What are the solutions to the equation z^2+0.2z-0.08=0 ?

The solutions to the equation z^2+0.2z-0.08=0 are z= 1/5 ,z=-2/5

Find the zeros of z^2+0.2z-0.08=0

The zeros of z^2+0.2z-0.08=0 are z= 1/5 ,z=-2/5

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z^{2} + 0.2 z - 0.08 = 0

z = \frac{1}{5}, z = - \frac{2}{5}

Decimal Notation

z = 0.2, z = - 0.4

Solution steps

z^{2} + 0.2 z - 0.08 = 0

Multiply both sides by

100

100 z^{2} + 20 z - 8 = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 \cdot 100 ( - 8 )}{2 \cdot 100}

2 0^{2} - 4 \cdot 100 (- 8) = 60

z_{1, 2} = \frac{- 20 \pm 60}{2 \cdot 100}

Separate the solutions

z_{1} = \frac{- 20 + 60}{2 \cdot 100}, z_{2} = \frac{- 20 - 60}{2 \cdot 100}

z = \frac{- 20 + 60}{2 \cdot 100} : \frac{1}{5}

z = \frac{- 20 - 60}{2 \cdot 100} : - \frac{2}{5}

The solutions to the quadratic equation are:

z = \frac{1}{5}, z = - \frac{2}{5}

x^{2} = x + 30

- 3 x^{2} + 15 = 0

15 q^{2} + 31 q + 15 = 5

(2 x + 1) (x + 1) + (2 x - 1) x = 7

n (4 + 2 n) - 4 (n - 6) = 74

What are the solutions to the equation z^2+0.2z-0.08=0 ?
The solutions to the equation z^2+0.2z-0.08=0 are z= 1/5 ,z=-2/5
Find the zeros of z^2+0.2z-0.08=0
The zeros of z^2+0.2z-0.08=0 are z= 1/5 ,z=-2/5