What are the solutions to the equation 6x^2+31x+18=0 ?

The solutions to the equation 6x^2+31x+18=0 are x=-2/3 ,x=-9/2

Find the zeros of 6x^2+31x+18=0

The zeros of 6x^2+31x+18=0 are x=-2/3 ,x=-9/2

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6 x^{2} + 31 x + 18 = 0

x = - \frac{2}{3}, x = - \frac{9}{2}

Decimal Notation

x = - 0.66666 \dots, x = - 4.5

Solution steps

6 x^{2} + 31 x + 18 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 31 \pm 3 1 ^{2} - 4 \cdot 6 \cdot 18}{2 \cdot 6}

3 1^{2} - 4 \cdot 6 \cdot 18 = 23

x_{1, 2} = \frac{- 31 \pm 23}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 31 + 23}{2 \cdot 6}, x_{2} = \frac{- 31 - 23}{2 \cdot 6}

x = \frac{- 31 + 23}{2 \cdot 6} : - \frac{2}{3}

x = \frac{- 31 - 23}{2 \cdot 6} : - \frac{9}{2}

The solutions to the quadratic equation are:

x = - \frac{2}{3}, x = - \frac{9}{2}

25 = x^{2} + (x + 1)^{2}

9 x^{2} + 5 = 6

- 2 x^{2} - 7 x + 13 = 0

x^{2} = 11664

12 x^{2} - 92 x + 130 = 0

What are the solutions to the equation 6x^2+31x+18=0 ?
The solutions to the equation 6x^2+31x+18=0 are x=-2/3 ,x=-9/2
Find the zeros of 6x^2+31x+18=0
The zeros of 6x^2+31x+18=0 are x=-2/3 ,x=-9/2