What are the solutions to the equation Q(Q+3)=5Q+3 ?

The solutions to the equation Q(Q+3)=5Q+3 are Q=3,Q=-1

Find the zeros of Q(Q+3)=5Q+3

The zeros of Q(Q+3)=5Q+3 are Q=3,Q=-1

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Q (Q + 3) = 5 Q + 3

Q = 3, Q = - 1

Solution steps

Q (Q + 3) = 5 Q + 3

Expand

Q (Q + 3) : Q^{2} + 3 Q

Q^{2} + 3 Q = 5 Q + 3

Move

3

to the left side

Q^{2} + 3 Q - 3 = 5 Q

Move

5 Q

to the left side

Q^{2} - 2 Q - 3 = 0

Solve with the quadratic formula

Q_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot ( - 3 )}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot (- 3) = 4

Q_{1, 2} = \frac{- ( - 2 ) \pm 4}{2 \cdot 1}

Separate the solutions

Q_{1} = \frac{- ( - 2 ) + 4}{2 \cdot 1}, Q_{2} = \frac{- ( - 2 ) - 4}{2 \cdot 1}

Q = \frac{- ( - 2 ) + 4}{2 \cdot 1} : 3

Q = \frac{- ( - 2 ) - 4}{2 \cdot 1} : - 1

The solutions to the quadratic equation are:

Q = 3, Q = - 1

x^{2} + 6 x + 5 = 0

2 x^{2} + 8 x + 2

5 x^{2} = - 15 x - 13

4 x^{2} + 28 x - 32 = 0

45 = 5 r^{2}

What are the solutions to the equation Q(Q+3)=5Q+3 ?
The solutions to the equation Q(Q+3)=5Q+3 are Q=3,Q=-1
Find the zeros of Q(Q+3)=5Q+3
The zeros of Q(Q+3)=5Q+3 are Q=3,Q=-1