What are the solutions to the equation 2(4x+3)^2-46=-12 ?

The solutions to the equation 2(4x+3)^2-46=-12 are x=(sqrt(17)-3)/4 ,x=(-sqrt(17)-3)/4

Find the zeros of 2(4x+3)^2-46=-12

The zeros of 2(4x+3)^2-46=-12 are x=(sqrt(17)-3)/4 ,x=(-sqrt(17)-3)/4

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2 (4 x + 3)^{2} - 46 = - 12

x = \frac{17 - 3}{4}, x = \frac{- 17 - 3}{4}

Decimal Notation

x = 0.28077 \dots, x = - 1.78077 \dots

Solution steps

2 (4 x + 3)^{2} - 46 = - 12

Move

46

to the right side

2 (4 x + 3)^{2} = 34

Divide both sides by

2

(4 x + 3)^{2} = 17

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

4 x + 3 = 17 : x = \frac{17 - 3}{4}

Solve

4 x + 3 = - 17 : x = \frac{- 17 - 3}{4}

The solutions to the quadratic equation are:

x = \frac{17 - 3}{4}, x = \frac{- 17 - 3}{4}

y, x^{2} - 2 x y + 3 y^{2} = 4

x^{2} - 15 = 1

x^{2} - 2 π x - 3 π^{2} = 0

12 x^{2} + 48 = 0

h^{2} - 3 h - 28 = 0

What are the solutions to the equation 2(4x+3)^2-46=-12 ?
The solutions to the equation 2(4x+3)^2-46=-12 are x=(sqrt(17)-3)/4 ,x=(-sqrt(17)-3)/4
Find the zeros of 2(4x+3)^2-46=-12
The zeros of 2(4x+3)^2-46=-12 are x=(sqrt(17)-3)/4 ,x=(-sqrt(17)-3)/4