What are the solutions to the equation completesquare 27-4x+x^2 ?

The solutions to the equation completesquare 27-4x+x^2 are (x-2)^2+23

Find the zeros of completesquare 27-4x+x^2

The zeros of completesquare 27-4x+x^2 are (x-2)^2+23

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complete the square

27 - 4 x + x^{2}

(x - 2)^{2} + 23

Solution steps

27 - 4 x + x^{2}

Write in the standard form

a x^{2} + b x + c

x^{2} - 4 x + 27

Write

x^{2} - 4 x + 27

in the form:

x^{2} + 2 a x + a^{2}

2 a = - 4 : a = - 2

Add and subtract

(- 2)^{2}

x^{2} - 4 x + 27 + (- 2)^{2} - (- 2)^{2}

x^{2} + 2 a x + a^{2} = (x + a)^{2}

x^{2} - 4 x + (- 2)^{2} = (x - 2)^{2}

(x - 2)^{2} + 27 - (- 2)^{2}

Simplify

(x - 2)^{2} + 23

8 x^{2} + 12 = 3 x^{2} + 27

y, x^{2} + x y + 2 y^{2} = 28

x^{2} - 3 x + 2 = 30

5 x^{2} - 4 x = - 2

x^{2} - 4 xx - 2 = 14 - 9 xx - 2

What are the solutions to the equation completesquare 27-4x+x^2 ?
The solutions to the equation completesquare 27-4x+x^2 are (x-2)^2+23
Find the zeros of completesquare 27-4x+x^2
The zeros of completesquare 27-4x+x^2 are (x-2)^2+23