What are the solutions to the equation 13x^2-16x=x^2-x ?

The solutions to the equation 13x^2-16x=x^2-x are x= 5/4 ,x=0

Find the zeros of 13x^2-16x=x^2-x

The zeros of 13x^2-16x=x^2-x are x= 5/4 ,x=0

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13 x^{2} - 16 x = x^{2} - x

x = \frac{5}{4}, x = 0

Decimal Notation

x = 1.25, x = 0

Solution steps

13 x^{2} - 16 x = x^{2} - x

Move

x

to the left side

13 x^{2} - 15 x = x^{2}

Move

x^{2}

to the left side

12 x^{2} - 15 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 15 ) \pm ( - 15 ) ^{2} - 4 \cdot 12 \cdot 0}{2 \cdot 12}

(- 15)^{2} - 4 \cdot 12 \cdot 0 = 15

x_{1, 2} = \frac{- ( - 15 ) \pm 15}{2 \cdot 12}

Separate the solutions

x_{1} = \frac{- ( - 15 ) + 15}{2 \cdot 12}, x_{2} = \frac{- ( - 15 ) - 15}{2 \cdot 12}

x = \frac{- ( - 15 ) + 15}{2 \cdot 12} : \frac{5}{4}

x = \frac{- ( - 15 ) - 15}{2 \cdot 12} : 0

The solutions to the quadratic equation are:

x = \frac{5}{4}, x = 0

\frac{2}{50}

5 x^{2} + 5 x + 1 = 0

8 a^{2} + 8 a + 2.4 = 0

- \frac{5}{8} + (- \frac{8}{5})

a^{5} - 6 a^{4} + 16 a^{3} - 32 a^{2} + 48 a - 32

What are the solutions to the equation 13x^2-16x=x^2-x ?
The solutions to the equation 13x^2-16x=x^2-x are x= 5/4 ,x=0
Find the zeros of 13x^2-16x=x^2-x
The zeros of 13x^2-16x=x^2-x are x= 5/4 ,x=0