What are the solutions to the equation 2x^2-13x-7=9x ?

The solutions to the equation 2x^2-13x-7=9x are x=(11+3sqrt(15))/2 ,x=(11-3sqrt(15))/2

Find the zeros of 2x^2-13x-7=9x

The zeros of 2x^2-13x-7=9x are x=(11+3sqrt(15))/2 ,x=(11-3sqrt(15))/2

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2 x^{2} - 13 x - 7 = 9 x

x = \frac{11 + 3 15}{2}, x = \frac{11 - 3 15}{2}

Decimal Notation

x = 11.30947 \dots, x = - 0.30947 \dots

Solution steps

2 x^{2} - 13 x - 7 = 9 x

Move

9 x

to the left side

2 x^{2} - 22 x - 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 22 ) \pm ( - 22 ) ^{2} - 4 \cdot 2 ( - 7 )}{2 \cdot 2}

(- 22)^{2} - 4 \cdot 2 (- 7) = 615

x_{1, 2} = \frac{- ( - 22 ) \pm 6 15}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 22 ) + 6 15}{2 \cdot 2}, x_{2} = \frac{- ( - 22 ) - 6 15}{2 \cdot 2}

x = \frac{- ( - 22 ) + 6 15}{2 \cdot 2} : \frac{11 + 3 15}{2}

x = \frac{- ( - 22 ) - 6 15}{2 \cdot 2} : \frac{11 - 3 15}{2}

The solutions to the quadratic equation are:

x = \frac{11 + 3 15}{2}, x = \frac{11 - 3 15}{2}

7 m^{2} - 24 m = - 9

t^{2} + 3 t - 19 = - 5

3 z^{2} - 7 z + 3 = 6

(- 4 - x) (1 - x) + 6 = 0

9 v^{2} = - 30 v - 25

What are the solutions to the equation 2x^2-13x-7=9x ?
The solutions to the equation 2x^2-13x-7=9x are x=(11+3sqrt(15))/2 ,x=(11-3sqrt(15))/2
Find the zeros of 2x^2-13x-7=9x
The zeros of 2x^2-13x-7=9x are x=(11+3sqrt(15))/2 ,x=(11-3sqrt(15))/2