What are the solutions to the equation x^2+31=-12x ?

The solutions to the equation x^2+31=-12x are x=-6+sqrt(5),x=-6-sqrt(5)

Find the zeros of x^2+31=-12x

The zeros of x^2+31=-12x are x=-6+sqrt(5),x=-6-sqrt(5)

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x^{2} + 31 = - 12 x

x = - 6 + 5, x = - 6 - 5

Decimal Notation

x = - 3.76393 \dots, x = - 8.23606 \dots

Solution steps

x^{2} + 31 = - 12 x

Move

12 x

to the left side

x^{2} + 31 + 12 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} + 12 x + 31 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 1 \cdot 31}{2 \cdot 1}

1 2^{2} - 4 \cdot 1 \cdot 31 = 25

x_{1, 2} = \frac{- 12 \pm 2 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 12 + 2 5}{2 \cdot 1}, x_{2} = \frac{- 12 - 2 5}{2 \cdot 1}

x = \frac{- 12 + 2 5}{2 \cdot 1} : - 6 + 5

x = \frac{- 12 - 2 5}{2 \cdot 1} : - 6 - 5

The solutions to the quadratic equation are:

x = - 6 + 5, x = - 6 - 5

2 x^{2} + 16 x + 26

x, 2 x^{2} - 7 x + 3 = 0

4 x^{2} + 268 = - 72 x

x^{2} + 7 x + 10 = 0

48 x + 12 x^{2} = 0

What are the solutions to the equation x^2+31=-12x ?
The solutions to the equation x^2+31=-12x are x=-6+sqrt(5),x=-6-sqrt(5)
Find the zeros of x^2+31=-12x
The zeros of x^2+31=-12x are x=-6+sqrt(5),x=-6-sqrt(5)