What are the solutions to the equation 3x^2+24x=-39 ?

The solutions to the equation 3x^2+24x=-39 are x=-4+sqrt(3),x=-4-sqrt(3)

Find the zeros of 3x^2+24x=-39

The zeros of 3x^2+24x=-39 are x=-4+sqrt(3),x=-4-sqrt(3)

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3 x^{2} + 24 x = - 39

x = - 4 + 3, x = - 4 - 3

Decimal Notation

x = - 2.26794 \dots, x = - 5.73205 \dots

Solution steps

3 x^{2} + 24 x = - 39

Move

39

to the left side

3 x^{2} + 24 x + 39 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 24 \pm 2 4 ^{2} - 4 \cdot 3 \cdot 39}{2 \cdot 3}

2 4^{2} - 4 \cdot 3 \cdot 39 = 63

x_{1, 2} = \frac{- 24 \pm 6 3}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 24 + 6 3}{2 \cdot 3}, x_{2} = \frac{- 24 - 6 3}{2 \cdot 3}

x = \frac{- 24 + 6 3}{2 \cdot 3} : - 4 + 3

x = \frac{- 24 - 6 3}{2 \cdot 3} : - 4 - 3

The solutions to the quadratic equation are:

x = - 4 + 3, x = - 4 - 3

18 - x^{2} = 13

y, 3 x^{2} + 4 y^{2} + 3 x y = 24

(x - 5)^{2} = 196

26 n^{2} + 41 n + 20 = 6 n^{2}

72 x^{2} + 288 x + 256 = 0

What are the solutions to the equation 3x^2+24x=-39 ?
The solutions to the equation 3x^2+24x=-39 are x=-4+sqrt(3),x=-4-sqrt(3)
Find the zeros of 3x^2+24x=-39
The zeros of 3x^2+24x=-39 are x=-4+sqrt(3),x=-4-sqrt(3)