What are the solutions to the equation 8m^2+19m+5=0 ?

The solutions to the equation 8m^2+19m+5=0 are m=(-19+sqrt(201))/(16),m=(-19-sqrt(201))/(16)

Find the zeros of 8m^2+19m+5=0

The zeros of 8m^2+19m+5=0 are m=(-19+sqrt(201))/(16),m=(-19-sqrt(201))/(16)

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8 m^{2} + 19 m + 5 = 0

m = \frac{- 19 + 201}{16}, m = \frac{- 19 - 201}{16}

Decimal Notation

m = - 0.30140 \dots, m = - 2.07359 \dots

Solution steps

8 m^{2} + 19 m + 5 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 19 \pm 1 9 ^{2} - 4 \cdot 8 \cdot 5}{2 \cdot 8}

1 9^{2} - 4 \cdot 8 \cdot 5 = 201

m_{1, 2} = \frac{- 19 \pm 201}{2 \cdot 8}

Separate the solutions

m_{1} = \frac{- 19 + 201}{2 \cdot 8}, m_{2} = \frac{- 19 - 201}{2 \cdot 8}

m = \frac{- 19 + 201}{2 \cdot 8} : \frac{- 19 + 201}{16}

m = \frac{- 19 - 201}{2 \cdot 8} : \frac{- 19 - 201}{16}

The solutions to the quadratic equation are:

m = \frac{- 19 + 201}{16}, m = \frac{- 19 - 201}{16}

3 x^{2} + 42 x = - 171

2 y^{2} + 9 y + 3 = 4

5 n^{2} - 7 n + 3 = 2

- 5 x^{2} = 60

- 2 x^{2} - 22 x - 3 = - 10 x + 13

What are the solutions to the equation 8m^2+19m+5=0 ?
The solutions to the equation 8m^2+19m+5=0 are m=(-19+sqrt(201))/(16),m=(-19-sqrt(201))/(16)
Find the zeros of 8m^2+19m+5=0
The zeros of 8m^2+19m+5=0 are m=(-19+sqrt(201))/(16),m=(-19-sqrt(201))/(16)