What are the solutions to the equation -1x^2+6x+4=0 ?

The solutions to the equation -1x^2+6x+4=0 are x=3-sqrt(13),x=3+sqrt(13)

Find the zeros of -1x^2+6x+4=0

The zeros of -1x^2+6x+4=0 are x=3-sqrt(13),x=3+sqrt(13)

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- 1 x^{2} + 6 x + 4 = 0

x = 3 - 13, x = 3 + 13

Decimal Notation

x = - 0.60555 \dots, x = 6.60555 \dots

Solution steps

- 1 \cdot x^{2} + 6 x + 4 = 0

Refine

- x^{2} + 6 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 ( - 1 ) \cdot 4}{2 ( - 1 )}

6^{2} - 4 (- 1) \cdot 4 = 213

x_{1, 2} = \frac{- 6 \pm 2 13}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 6 + 2 13}{2 ( - 1 )}, x_{2} = \frac{- 6 - 2 13}{2 ( - 1 )}

x = \frac{- 6 + 2 13}{2 ( - 1 )} : 3 - 13

x = \frac{- 6 - 2 13}{2 ( - 1 )} : 3 + 13

The solutions to the quadratic equation are:

x = 3 - 13, x = 3 + 13

x^{2} + 15 x - 800 = 0

2 a^{2} - a - 11 = - 3

x^{2} - 16 x = - 73

25 x^{2} - 16 = 0

2 z^{2} + 5.5 z + 3.75 = 0

What are the solutions to the equation -1x^2+6x+4=0 ?
The solutions to the equation -1x^2+6x+4=0 are x=3-sqrt(13),x=3+sqrt(13)
Find the zeros of -1x^2+6x+4=0
The zeros of -1x^2+6x+4=0 are x=3-sqrt(13),x=3+sqrt(13)