What are the solutions to the equation x^2-14x+62=-77 ?

The solutions to the equation x^2-14x+62=-77 are x=7+3sqrt(10)i,x=7-3sqrt(10)i

Find the zeros of x^2-14x+62=-77

The zeros of x^2-14x+62=-77 are x=7+3sqrt(10)i,x=7-3sqrt(10)i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} - 14 x + 62 = - 77

x = 7 + 310 i, x = 7 - 310 i

Solution steps

x^{2} - 14 x + 62 = - 77

Move

77

to the left side

x^{2} - 14 x + 139 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 14 ) \pm ( - 14 ) ^{2} - 4 \cdot 1 \cdot 139}{2 \cdot 1}

Simplify

(- 14)^{2} - 4 \cdot 1 \cdot 139 : 610 i

x_{1, 2} = \frac{- ( - 14 ) \pm 6 10 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 14 ) + 6 10 i}{2 \cdot 1}, x_{2} = \frac{- ( - 14 ) - 6 10 i}{2 \cdot 1}

x = \frac{- ( - 14 ) + 6 10 i}{2 \cdot 1} : 7 + 310 i

x = \frac{- ( - 14 ) - 6 10 i}{2 \cdot 1} : 7 - 310 i

The solutions to the quadratic equation are:

x = 7 + 310 i, x = 7 - 310 i

25 (1 - 4 x)^{2} - 28 = - 12

x^{2} - 4 x = 4 x

(x - 3)^{2} = \frac{x ^{2} - 9}{3}

0 = 34 x + 60 - (2 x^{2} + 200)

x, x^{2} + 2 y^{5} = 10 x y

What are the solutions to the equation x^2-14x+62=-77 ?
The solutions to the equation x^2-14x+62=-77 are x=7+3sqrt(10)i,x=7-3sqrt(10)i
Find the zeros of x^2-14x+62=-77
The zeros of x^2-14x+62=-77 are x=7+3sqrt(10)i,x=7-3sqrt(10)i