What are the solutions to the equation 7m^2-m-4=6m^2 ?

The solutions to the equation 7m^2-m-4=6m^2 are m=(1+sqrt(17))/2 ,m=(1-sqrt(17))/2

Find the zeros of 7m^2-m-4=6m^2

The zeros of 7m^2-m-4=6m^2 are m=(1+sqrt(17))/2 ,m=(1-sqrt(17))/2

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7 m^{2} - m - 4 = 6 m^{2}

m = \frac{1 + 17}{2}, m = \frac{1 - 17}{2}

Decimal Notation

m = 2.56155 \dots, m = - 1.56155 \dots

Solution steps

7 m^{2} - m - 4 = 6 m^{2}

Move

6 m^{2}

to the left side

m^{2} - m - 4 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot ( - 4 )}{2 \cdot 1}

(- 1)^{2} - 4 \cdot 1 \cdot (- 4) = 17

m_{1, 2} = \frac{- ( - 1 ) \pm 17}{2 \cdot 1}

Separate the solutions

m_{1} = \frac{- ( - 1 ) + 17}{2 \cdot 1}, m_{2} = \frac{- ( - 1 ) - 17}{2 \cdot 1}

m = \frac{- ( - 1 ) + 17}{2 \cdot 1} : \frac{1 + 17}{2}

m = \frac{- ( - 1 ) - 17}{2 \cdot 1} : \frac{1 - 17}{2}

The solutions to the quadratic equation are:

m = \frac{1 + 17}{2}, m = \frac{1 - 17}{2}

s^{2} + s + 100

(x + 10) (- x - 8) = 0

2 x^{2} - 2 x - 12 = 0

4 x^{2} - 15 x + 12 = 0

y, 3 x^{2} - 6 x y + y^{2} = 2 x - y

What are the solutions to the equation 7m^2-m-4=6m^2 ?
The solutions to the equation 7m^2-m-4=6m^2 are m=(1+sqrt(17))/2 ,m=(1-sqrt(17))/2
Find the zeros of 7m^2-m-4=6m^2
The zeros of 7m^2-m-4=6m^2 are m=(1+sqrt(17))/2 ,m=(1-sqrt(17))/2