What are the solutions to the equation roots x^2-2x-5 ?

The solutions to the equation roots x^2-2x-5 are x=1+sqrt(6),x=1-sqrt(6)

Find the zeros of roots x^2-2x-5

The zeros of roots x^2-2x-5 are x=1+sqrt(6),x=1-sqrt(6)

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roots

x^{2} - 2 x - 5

x = 1 + 6, x = 1 - 6

Solution steps

x^{2} - 2 x - 5

The roots are the intercepts with the x-axis

(y = 0)

x^{2} - 2 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot ( - 5 )}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot (- 5) = 26

x_{1, 2} = \frac{- ( - 2 ) \pm 2 6}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2 6}{2 \cdot 1}, x_{2} = \frac{- ( - 2 ) - 2 6}{2 \cdot 1}

x = \frac{- ( - 2 ) + 2 6}{2 \cdot 1} : 1 + 6

x = \frac{- ( - 2 ) - 2 6}{2 \cdot 1} : 1 - 6

The solutions to the quadratic equation are:

x = 1 + 6, x = 1 - 6

3 x + 2 = - 2 x^{2} + 3 x + 6

6 p^{2} = 42

3 m^{2} + 15 m + 25.5 = 0

y, y^{2} + y + 3 x + 1 = 0

y, 3 x^{2} + 3 y^{2} = 0

What are the solutions to the equation roots x^2-2x-5 ?
The solutions to the equation roots x^2-2x-5 are x=1+sqrt(6),x=1-sqrt(6)
Find the zeros of roots x^2-2x-5
The zeros of roots x^2-2x-5 are x=1+sqrt(6),x=1-sqrt(6)