What are the solutions to the equation 16x^2-25x=-9 ?

The solutions to the equation 16x^2-25x=-9 are x=1,x= 9/16

Find the zeros of 16x^2-25x=-9

The zeros of 16x^2-25x=-9 are x=1,x= 9/16

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16 x^{2} - 25 x = - 9

x = 1, x = \frac{9}{16}

Decimal Notation

x = 1, x = 0.5625

Solution steps

16 x^{2} - 25 x = - 9

Move

9

to the left side

16 x^{2} - 25 x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 25 ) \pm ( - 25 ) ^{2} - 4 \cdot 16 \cdot 9}{2 \cdot 16}

(- 25)^{2} - 4 \cdot 16 \cdot 9 = 7

x_{1, 2} = \frac{- ( - 25 ) \pm 7}{2 \cdot 16}

Separate the solutions

x_{1} = \frac{- ( - 25 ) + 7}{2 \cdot 16}, x_{2} = \frac{- ( - 25 ) - 7}{2 \cdot 16}

x = \frac{- ( - 25 ) + 7}{2 \cdot 16} : 1

x = \frac{- ( - 25 ) - 7}{2 \cdot 16} : \frac{9}{16}

The solutions to the quadratic equation are:

x = 1, x = \frac{9}{16}

- x^{2} + 2 x = 2

8 x^{2} + 7 = 5 x^{2} + 4

7 t (t + (17)) = - 420

6 x^{2} + 45 x + 21 = 0

x^{2} + 12 x + c

What are the solutions to the equation 16x^2-25x=-9 ?
The solutions to the equation 16x^2-25x=-9 are x=1,x= 9/16
Find the zeros of 16x^2-25x=-9
The zeros of 16x^2-25x=-9 are x=1,x= 9/16