What are the solutions to the equation 2x^2-9x+21=0 ?

The solutions to the equation 2x^2-9x+21=0 are x= 9/4+i(sqrt(87))/4 ,x= 9/4-i(sqrt(87))/4

Find the zeros of 2x^2-9x+21=0

The zeros of 2x^2-9x+21=0 are x= 9/4+i(sqrt(87))/4 ,x= 9/4-i(sqrt(87))/4

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2 x^{2} - 9 x + 21 = 0

x = \frac{9}{4} + i \frac{87}{4}, x = \frac{9}{4} - i \frac{87}{4}

Solution steps

2 x^{2} - 9 x + 21 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 2 \cdot 21}{2 \cdot 2}

Simplify

(- 9)^{2} - 4 \cdot 2 \cdot 21 : 87 i

x_{1, 2} = \frac{- ( - 9 ) \pm 87 i}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 9 ) + 87 i}{2 \cdot 2}, x_{2} = \frac{- ( - 9 ) - 87 i}{2 \cdot 2}

x = \frac{- ( - 9 ) + 87 i}{2 \cdot 2} : \frac{9}{4} + i \frac{87}{4}

x = \frac{- ( - 9 ) - 87 i}{2 \cdot 2} : \frac{9}{4} - i \frac{87}{4}

The solutions to the quadratic equation are:

x = \frac{9}{4} + i \frac{87}{4}, x = \frac{9}{4} - i \frac{87}{4}

y, y^{2} - 3 x y + 5 x^{2} y = 13 + x y^{2}

x^{2} + 10 x + 21 = 0

4 z^{2} + 11 z + 3 = - 1

9 u^{2} + 25 = - 30 u

x^{2} + 5 x + \frac{9}{4}

What are the solutions to the equation 2x^2-9x+21=0 ?
The solutions to the equation 2x^2-9x+21=0 are x= 9/4+i(sqrt(87))/4 ,x= 9/4-i(sqrt(87))/4
Find the zeros of 2x^2-9x+21=0
The zeros of 2x^2-9x+21=0 are x= 9/4+i(sqrt(87))/4 ,x= 9/4-i(sqrt(87))/4