What are the solutions to the equation 18x^2-6=8x ?

The solutions to the equation 18x^2-6=8x are x=(2+sqrt(31))/9 ,x=(2-sqrt(31))/9

Find the zeros of 18x^2-6=8x

The zeros of 18x^2-6=8x are x=(2+sqrt(31))/9 ,x=(2-sqrt(31))/9

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18 x^{2} - 6 = 8 x

x = \frac{2 + 31}{9}, x = \frac{2 - 31}{9}

Decimal Notation

x = 0.84086 \dots, x = - 0.39641 \dots

Solution steps

18 x^{2} - 6 = 8 x

Move

8 x

to the left side

18 x^{2} - 6 - 8 x = 0

Write in the standard form

a x^{2} + b x + c = 0

18 x^{2} - 8 x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 18 ( - 6 )}{2 \cdot 18}

(- 8)^{2} - 4 \cdot 18 (- 6) = 431

x_{1, 2} = \frac{- ( - 8 ) \pm 4 31}{2 \cdot 18}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 4 31}{2 \cdot 18}, x_{2} = \frac{- ( - 8 ) - 4 31}{2 \cdot 18}

x = \frac{- ( - 8 ) + 4 31}{2 \cdot 18} : \frac{2 + 31}{9}

x = \frac{- ( - 8 ) - 4 31}{2 \cdot 18} : \frac{2 - 31}{9}

The solutions to the quadratic equation are:

x = \frac{2 + 31}{9}, x = \frac{2 - 31}{9}

y, x^{2} + x y + y^{2} = 4

3 x^{2} + 2 x + 5 = 2 x + 17

x = x^{2} + 4 x + 2

r^{2} + 4

4 x^{2} + 28 x = - 53

What are the solutions to the equation 18x^2-6=8x ?
The solutions to the equation 18x^2-6=8x are x=(2+sqrt(31))/9 ,x=(2-sqrt(31))/9
Find the zeros of 18x^2-6=8x
The zeros of 18x^2-6=8x are x=(2+sqrt(31))/9 ,x=(2-sqrt(31))/9