What are the solutions to the equation solvefor v,(mv^2)/r =qvB ?

The solutions to the equation solvefor v,(mv^2)/r =qvB are v=(rqB)/m ,v=0;\quad m\ne 0

Find the zeros of solvefor v,(mv^2)/r =qvB

The zeros of solvefor v,(mv^2)/r =qvB are v=(rqB)/m ,v=0;\quad m\ne 0

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solve for

v, \frac{m v ^{2}}{r} = q v B

v = \frac{r qB}{m}, v = 0; m \neq = 0

Solution steps

\frac{m v ^{2}}{r} = q v B

Multiply both sides by

r

m v^{2} = v r qB; r \neq = 0

Move

v r qB

to the left side

m v^{2} - v r qB = 0; r \neq = 0

Write in the standard form

a x^{2} + b x + c = 0

m v^{2} - r qB v = 0; r \neq = 0

Solve with the quadratic formula

v_{1, 2} = \frac{- ( - r qB ) \pm ( - r qB ) ^{2} - 4 m \cdot 0}{2 m}

Simplify

(- r qB)^{2} - 4 m \cdot 0 : r qB

v_{1, 2} = \frac{- ( - r qB ) \pm r qB}{2 m}; m \neq = 0

Separate the solutions

v_{1} = \frac{- ( - r qB ) + r qB}{2 m}, v_{2} = \frac{- ( - r qB ) - r qB}{2 m}

v = \frac{- ( - r qB ) + r qB}{2 m} : \frac{r qB}{m}

v = \frac{- ( - r qB ) - r qB}{2 m} : 0

The solutions to the quadratic equation are:

v = \frac{r qB}{m}, v = 0; m \neq = 0

\frac{1}{6} z^{2} + \frac{4}{6} z = 2

x^{2} - 8 x + 16 = 0

x^{2} + 3 x + 3 = - 2 x - 3

289 x^{2} + 378 x + 89 = 0

y, x y^{2} - 2 x^{3} = 2

What are the solutions to the equation solvefor v,(mv^2)/r =qvB ?
The solutions to the equation solvefor v,(mv^2)/r =qvB are v=(rqB)/m ,v=0;\quad m\ne 0
Find the zeros of solvefor v,(mv^2)/r =qvB
The zeros of solvefor v,(mv^2)/r =qvB are v=(rqB)/m ,v=0;\quad m\ne 0