What are the solutions to the equation x^2+7x-23/4 =0 ?

The solutions to the equation x^2+7x-23/4 =0 are x=(-7+6sqrt(2))/2 ,x=-(7+6sqrt(2))/2

Find the zeros of x^2+7x-23/4 =0

The zeros of x^2+7x-23/4 =0 are x=(-7+6sqrt(2))/2 ,x=-(7+6sqrt(2))/2

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x^{2} + 7 x - \frac{23}{4} = 0

x = \frac{- 7 + 6 2}{2}, x = - \frac{7 + 6 2}{2}

Decimal Notation

x = 0.74264 \dots, x = - 7.74264 \dots

Solution steps

x^{2} + 7 x - \frac{23}{4} = 0

Multiply both sides by

4

4 x^{2} + 28 x - 23 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 28 \pm 2 8 ^{2} - 4 \cdot 4 ( - 23 )}{2 \cdot 4}

2 8^{2} - 4 \cdot 4 (- 23) = 242

x_{1, 2} = \frac{- 28 \pm 24 2}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 28 + 24 2}{2 \cdot 4}, x_{2} = \frac{- 28 - 24 2}{2 \cdot 4}

x = \frac{- 28 + 24 2}{2 \cdot 4} : \frac{- 7 + 6 2}{2}

x = \frac{- 28 - 24 2}{2 \cdot 4} : - \frac{7 + 6 2}{2}

The solutions to the quadratic equation are:

x = \frac{- 7 + 6 2}{2}, x = - \frac{7 + 6 2}{2}

- 5 x^{2} + 5 = 0

y, x^{2} y - 4 x = 5

2 x^{2} + 6 x = - 4

y, x^{2} y^{2} = 3 x

x^{2} - 40 = - 6 x

What are the solutions to the equation x^2+7x-23/4 =0 ?
The solutions to the equation x^2+7x-23/4 =0 are x=(-7+6sqrt(2))/2 ,x=-(7+6sqrt(2))/2
Find the zeros of x^2+7x-23/4 =0
The zeros of x^2+7x-23/4 =0 are x=(-7+6sqrt(2))/2 ,x=-(7+6sqrt(2))/2