What are the solutions to the equation 36=x^2+x^2 ?

The solutions to the equation 36=x^2+x^2 are x=3sqrt(2),x=-3sqrt(2)

Find the zeros of 36=x^2+x^2

The zeros of 36=x^2+x^2 are x=3sqrt(2),x=-3sqrt(2)

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36 = x^{2} + x^{2}

x = 32, x = - 32

Decimal Notation

x = 4.24264 \dots, x = - 4.24264 \dots

Solution steps

36 = x^{2} + x^{2}

Switch sides

x^{2} + x^{2} = 36

Add similar elements:

x^{2} + x^{2} = 2 x^{2}

2 x^{2} = 36

Divide both sides by

2

x^{2} = 18

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 18, x = - 18

18 = 32

- 18 = - 32

x = 32, x = - 32

y, x^{2} + x y - 2 y^{2} = 0

\frac{w ^{2}}{6} - \frac{w}{3} - 4 = 0

x^{2} + 8 x - 49 = - 4

3 (4 x + 3)^{2} + 1 = 16

\frac{x}{3} x + 10 = 15

What are the solutions to the equation 36=x^2+x^2 ?
The solutions to the equation 36=x^2+x^2 are x=3sqrt(2),x=-3sqrt(2)
Find the zeros of 36=x^2+x^2
The zeros of 36=x^2+x^2 are x=3sqrt(2),x=-3sqrt(2)