What are the solutions to the equation (x-4)(1+x)=0 ?

The solutions to the equation (x-4)(1+x)=0 are x=4,x=-1

Find the zeros of (x-4)(1+x)=0

The zeros of (x-4)(1+x)=0 are x=4,x=-1

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(x - 4) (1 + x) = 0

x = 4, x = - 1

Solution steps

(x - 4) (1 + x) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 4 = 0 or 1 + x = 0

Solve

x - 4 = 0 : x = 4

Solve

1 + x = 0 : x = - 1

The solutions to the quadratic equation are:

x = 4, x = - 1

- 3 x^{2} + 5 x - 1 = 5 x^{2} - 8 x - 3

x^{2} - 25 x + 9

x^{2} - 2 x = 24

(x - 2)^{2} = 3 x - 2

h^{2} + 5 h = 295

What are the solutions to the equation (x-4)(1+x)=0 ?
The solutions to the equation (x-4)(1+x)=0 are x=4,x=-1
Find the zeros of (x-4)(1+x)=0
The zeros of (x-4)(1+x)=0 are x=4,x=-1