What are the solutions to the equation 14+2x^2=24 ?

The solutions to the equation 14+2x^2=24 are x=sqrt(5),x=-sqrt(5)

Find the zeros of 14+2x^2=24

The zeros of 14+2x^2=24 are x=sqrt(5),x=-sqrt(5)

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14 + 2 x^{2} = 24

x = 5, x = - 5

Decimal Notation

x = 2.23606 \dots, x = - 2.23606 \dots

Solution steps

14 + 2 x^{2} = 24

Move

14

to the right side

2 x^{2} = 10

Divide both sides by

2

x^{2} = 5

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 5, x = - 5

m^{2} + 3 m - 108 = 0

10 x + 4 - 6 x^{2} = 2 x^{2} + 5 x - 27

p, p^{2} - 18 q = 0

44.118 x^{2} - 401.28 x + 182.568 = 0

2 x^{2} - 6 x + 11

What are the solutions to the equation 14+2x^2=24 ?
The solutions to the equation 14+2x^2=24 are x=sqrt(5),x=-sqrt(5)
Find the zeros of 14+2x^2=24
The zeros of 14+2x^2=24 are x=sqrt(5),x=-sqrt(5)