What are the solutions to the equation (1-x)^2=e^3 ?

The solutions to the equation (1-x)^2=e^3 are x=-esqrt(e)+1,x=esqrt(e)+1

Find the zeros of (1-x)^2=e^3

The zeros of (1-x)^2=e^3 are x=-esqrt(e)+1,x=esqrt(e)+1

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(1 - x)^{2} = e^{3}

x = - e e + 1, x = e e + 1

Decimal Notation

x = - 3.48168 \dots, x = 5.48168 \dots

Solution steps

(1 - x)^{2} = e^{3}

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

1 - x = e^{3} : x = - e e + 1

Solve

1 - x = - e^{3} : x = e e + 1

The solutions to the quadratic equation are:

x = - e e + 1, x = e e + 1

- k^{2} - 3 k - 2 = - 5 k^{2}

x^{2} = 10 - 3 x

9 x^{2} - 12 x + 13 = 0

3 x^{2} = 400

x, 4 x^{2} + y^{2} + 4 z^{2} - 4 y - 24 z + 36 = 0

What are the solutions to the equation (1-x)^2=e^3 ?
The solutions to the equation (1-x)^2=e^3 are x=-esqrt(e)+1,x=esqrt(e)+1
Find the zeros of (1-x)^2=e^3
The zeros of (1-x)^2=e^3 are x=-esqrt(e)+1,x=esqrt(e)+1