What are the solutions to the equation 9x^2+12x+11=6x^2 ?

The solutions to the equation 9x^2+12x+11=6x^2 are x=(-6+sqrt(3))/3 ,x=-(6+sqrt(3))/3

Find the zeros of 9x^2+12x+11=6x^2

The zeros of 9x^2+12x+11=6x^2 are x=(-6+sqrt(3))/3 ,x=-(6+sqrt(3))/3

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9 x^{2} + 12 x + 11 = 6 x^{2}

x = \frac{- 6 + 3}{3}, x = - \frac{6 + 3}{3}

Decimal Notation

x = - 1.42264 \dots, x = - 2.57735 \dots

Solution steps

9 x^{2} + 12 x + 11 = 6 x^{2}

Move

6 x^{2}

to the left side

3 x^{2} + 12 x + 11 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 3 \cdot 11}{2 \cdot 3}

1 2^{2} - 4 \cdot 3 \cdot 11 = 23

x_{1, 2} = \frac{- 12 \pm 2 3}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 12 + 2 3}{2 \cdot 3}, x_{2} = \frac{- 12 - 2 3}{2 \cdot 3}

x = \frac{- 12 + 2 3}{2 \cdot 3} : \frac{- 6 + 3}{3}

x = \frac{- 12 - 2 3}{2 \cdot 3} : - \frac{6 + 3}{3}

The solutions to the quadratic equation are:

x = \frac{- 6 + 3}{3}, x = - \frac{6 + 3}{3}

- \frac{4}{7} x^{2} + 28 = 0

(1 - 4 x)^{2} + 5 = (2 - 3 x) (1 - 5 x)

- 2 x^{2} + 100 x = 0

18 x^{2} - 36 x - 144 = 0

n^{2} - 5 n + 6 = 5 n

What are the solutions to the equation 9x^2+12x+11=6x^2 ?
The solutions to the equation 9x^2+12x+11=6x^2 are x=(-6+sqrt(3))/3 ,x=-(6+sqrt(3))/3
Find the zeros of 9x^2+12x+11=6x^2
The zeros of 9x^2+12x+11=6x^2 are x=(-6+sqrt(3))/3 ,x=-(6+sqrt(3))/3