What are the solutions to the equation completesquare 3x^2=-4+8x ?

The solutions to the equation completesquare 3x^2=-4+8x are x=2,x= 2/3

Find the zeros of completesquare 3x^2=-4+8x

The zeros of completesquare 3x^2=-4+8x are x=2,x= 2/3

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3 x^{2} = - 4 + 8 x

x = 2, x = \frac{2}{3}

Decimal Notation

x = 2, x = 0.66666 \dots

Solution steps

3 x^{2} = - 4 + 8 x

Move

8 x

to the left side

3 x^{2} - 8 x = - 4

Divide both sides by

3

\frac{3 x ^{2} - 8 x}{3} = \frac{- 4}{3}

x^{2} - \frac{8 x}{3} = - \frac{4}{3}

Rewrite in the form

(x + a)^{2} = b

(x - \frac{4}{3})^{2} = \frac{4}{9}

For

the solutions are

f (x) = a, - a

Solve

x - \frac{4}{3} = \frac{4}{9} : x = 2

Solve

x - \frac{4}{3} = - \frac{4}{9} : x = \frac{2}{3}

The solutions to the quadratic equation are:

x = 2, x = \frac{2}{3}

121 x^{2} - 64 = 0

r^{2} + 12 r + 17 = 0

x^{2} - x + 4

9 x^{2} - 15 x - 6 = 0

(40 - x) (60 - x) = 800

What are the solutions to the equation completesquare 3x^2=-4+8x ?
The solutions to the equation completesquare 3x^2=-4+8x are x=2,x= 2/3
Find the zeros of completesquare 3x^2=-4+8x
The zeros of completesquare 3x^2=-4+8x are x=2,x= 2/3