What are the solutions to the equation 4w^2-19w+21=2 ?

The solutions to the equation 4w^2-19w+21=2 are w=(19+sqrt(57))/8 ,w=(19-sqrt(57))/8

Find the zeros of 4w^2-19w+21=2

The zeros of 4w^2-19w+21=2 are w=(19+sqrt(57))/8 ,w=(19-sqrt(57))/8

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4 w^{2} - 19 w + 21 = 2

w = \frac{19 + 57}{8}, w = \frac{19 - 57}{8}

Decimal Notation

w = 3.31872 \dots, w = 1.43127 \dots

Solution steps

4 w^{2} - 19 w + 21 = 2

Move

2

to the left side

4 w^{2} - 19 w + 19 = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- ( - 19 ) \pm ( - 19 ) ^{2} - 4 \cdot 4 \cdot 19}{2 \cdot 4}

(- 19)^{2} - 4 \cdot 4 \cdot 19 = 57

w_{1, 2} = \frac{- ( - 19 ) \pm 57}{2 \cdot 4}

Separate the solutions

w_{1} = \frac{- ( - 19 ) + 57}{2 \cdot 4}, w_{2} = \frac{- ( - 19 ) - 57}{2 \cdot 4}

w = \frac{- ( - 19 ) + 57}{2 \cdot 4} : \frac{19 + 57}{8}

w = \frac{- ( - 19 ) - 57}{2 \cdot 4} : \frac{19 - 57}{8}

The solutions to the quadratic equation are:

w = \frac{19 + 57}{8}, w = \frac{19 - 57}{8}

y, x^{2} + y^{2} - 4 x + 6 y + 13 = 0

2^{2} + 21^{2} = x^{2}

9 x^{2} - 6 x - 7 = 0

(x - 1)^{2} = 121

a, a^{2} = b^{2} + c^{2}

What are the solutions to the equation 4w^2-19w+21=2 ?
The solutions to the equation 4w^2-19w+21=2 are w=(19+sqrt(57))/8 ,w=(19-sqrt(57))/8
Find the zeros of 4w^2-19w+21=2
The zeros of 4w^2-19w+21=2 are w=(19+sqrt(57))/8 ,w=(19-sqrt(57))/8