What are the solutions to the equation 10=3Q^2-18Q+5 ?

The solutions to the equation 10=3Q^2-18Q+5 are Q=(9+4sqrt(6))/3 ,Q=(9-4sqrt(6))/3

Find the zeros of 10=3Q^2-18Q+5

The zeros of 10=3Q^2-18Q+5 are Q=(9+4sqrt(6))/3 ,Q=(9-4sqrt(6))/3

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10 = 3 Q^{2} - 18 Q + 5

Q = \frac{9 + 4 6}{3}, Q = \frac{9 - 4 6}{3}

Decimal Notation

Q = 6.26598 \dots, Q = - 0.26598 \dots

Solution steps

10 = 3 Q^{2} - 18 Q + 5

Switch sides

3 Q^{2} - 18 Q + 5 = 10

Move

10

to the left side

3 Q^{2} - 18 Q - 5 = 0

Solve with the quadratic formula

Q_{1, 2} = \frac{- ( - 18 ) \pm ( - 18 ) ^{2} - 4 \cdot 3 ( - 5 )}{2 \cdot 3}

(- 18)^{2} - 4 \cdot 3 (- 5) = 86

Q_{1, 2} = \frac{- ( - 18 ) \pm 8 6}{2 \cdot 3}

Separate the solutions

Q_{1} = \frac{- ( - 18 ) + 8 6}{2 \cdot 3}, Q_{2} = \frac{- ( - 18 ) - 8 6}{2 \cdot 3}

Q = \frac{- ( - 18 ) + 8 6}{2 \cdot 3} : \frac{9 + 4 6}{3}

Q = \frac{- ( - 18 ) - 8 6}{2 \cdot 3} : \frac{9 - 4 6}{3}

The solutions to the quadratic equation are:

Q = \frac{9 + 4 6}{3}, Q = \frac{9 - 4 6}{3}

s^{2} + 4 s + 13

4 x^{2} + 11 x - 108 = 0

y, x^{4} y - 8 x y + 3 x y^{2} = 9

x^{2} = - 147

x^{2} = - 166

What are the solutions to the equation 10=3Q^2-18Q+5 ?
The solutions to the equation 10=3Q^2-18Q+5 are Q=(9+4sqrt(6))/3 ,Q=(9-4sqrt(6))/3
Find the zeros of 10=3Q^2-18Q+5
The zeros of 10=3Q^2-18Q+5 are Q=(9+4sqrt(6))/3 ,Q=(9-4sqrt(6))/3