What are the solutions to the equation -3x^2-5x+15=7 ?

The solutions to the equation -3x^2-5x+15=7 are x=-8/3 ,x=1

Find the zeros of -3x^2-5x+15=7

The zeros of -3x^2-5x+15=7 are x=-8/3 ,x=1

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- 3 x^{2} - 5 x + 15 = 7

x = - \frac{8}{3}, x = 1

Decimal Notation

x = - 2.66666 \dots, x = 1

Solution steps

- 3 x^{2} - 5 x + 15 = 7

Move

7

to the left side

- 3 x^{2} - 5 x + 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 ( - 3 ) \cdot 8}{2 ( - 3 )}

(- 5)^{2} - 4 (- 3) \cdot 8 = 11

x_{1, 2} = \frac{- ( - 5 ) \pm 11}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 11}{2 ( - 3 )}, x_{2} = \frac{- ( - 5 ) - 11}{2 ( - 3 )}

x = \frac{- ( - 5 ) + 11}{2 ( - 3 )} : - \frac{8}{3}

x = \frac{- ( - 5 ) - 11}{2 ( - 3 )} : 1

The solutions to the quadratic equation are:

x = - \frac{8}{3}, x = 1

6 p^{2} - 7 p + 2 = 0

3 x^{2} - x - 52 = 0

- 4 x^{2} = 72

5 x^{2} + 9 = 3 x^{2} + 27

y, 4 x^{2} - 9 y^{2} - 8 x + 18 y - 1 = 0

What are the solutions to the equation -3x^2-5x+15=7 ?
The solutions to the equation -3x^2-5x+15=7 are x=-8/3 ,x=1
Find the zeros of -3x^2-5x+15=7
The zeros of -3x^2-5x+15=7 are x=-8/3 ,x=1