What are the solutions to the equation -18x^2-12=0 ?

The solutions to the equation -18x^2-12=0 are x=sqrt(2/3)i,x=-sqrt(2/3)i

Find the zeros of -18x^2-12=0

The zeros of -18x^2-12=0 are x=sqrt(2/3)i,x=-sqrt(2/3)i

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- 18 x^{2} - 12 = 0

x = \frac{2}{3} i, x = - \frac{2}{3} i

Solution steps

- 18 x^{2} - 12 = 0

Move

12

to the right side

- 18 x^{2} = 12

Divide both sides by

- 18

x^{2} = - \frac{2}{3}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - \frac{2}{3}, x = - - \frac{2}{3}

- \frac{2}{3} = \frac{2}{3} i

- - \frac{2}{3} = - \frac{2}{3} i

x = \frac{2}{3} i, x = - \frac{2}{3} i

x^{2} + c x + 1 = 0

t^{2} + 8 t + 19 = 0

16 (x^{2} - 4) + 5 = - 10

7 x^{2} + 42 x - 50 = 6

0 = 32 - 2 t - 5 t^{2}

What are the solutions to the equation -18x^2-12=0 ?
The solutions to the equation -18x^2-12=0 are x=sqrt(2/3)i,x=-sqrt(2/3)i
Find the zeros of -18x^2-12=0
The zeros of -18x^2-12=0 are x=sqrt(2/3)i,x=-sqrt(2/3)i