What are the solutions to the equation 3k^2+9k-20=2k ?

The solutions to the equation 3k^2+9k-20=2k are k= 5/3 ,k=-4

Find the zeros of 3k^2+9k-20=2k

The zeros of 3k^2+9k-20=2k are k= 5/3 ,k=-4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3 k^{2} + 9 k - 20 = 2 k

k = \frac{5}{3}, k = - 4

Decimal Notation

k = 1.66666 \dots, k = - 4

Solution steps

3 k^{2} + 9 k - 20 = 2 k

Move

2 k

to the left side

3 k^{2} + 7 k - 20 = 0

Solve with the quadratic formula

k_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 3 ( - 20 )}{2 \cdot 3}

7^{2} - 4 \cdot 3 (- 20) = 17

k_{1, 2} = \frac{- 7 \pm 17}{2 \cdot 3}

Separate the solutions

k_{1} = \frac{- 7 + 17}{2 \cdot 3}, k_{2} = \frac{- 7 - 17}{2 \cdot 3}

k = \frac{- 7 + 17}{2 \cdot 3} : \frac{5}{3}

k = \frac{- 7 - 17}{2 \cdot 3} : - 4

The solutions to the quadratic equation are:

k = \frac{5}{3}, k = - 4

h^{2} + 19 h = 0

3 x^{2} - 10 x = - 7

y^{2} = - 15

2 x^{2} + 8 x + 11 = 0

x^{2} = x + 30

What are the solutions to the equation 3k^2+9k-20=2k ?
The solutions to the equation 3k^2+9k-20=2k are k= 5/3 ,k=-4
Find the zeros of 3k^2+9k-20=2k
The zeros of 3k^2+9k-20=2k are k= 5/3 ,k=-4