What are the solutions to the equation 4s^2+2s+1=0 ?

The solutions to the equation 4s^2+2s+1=0 are s=-1/4+i(sqrt(3))/4 ,s=-1/4-i(sqrt(3))/4

Find the zeros of 4s^2+2s+1=0

The zeros of 4s^2+2s+1=0 are s=-1/4+i(sqrt(3))/4 ,s=-1/4-i(sqrt(3))/4

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4 s^{2} + 2 s + 1 = 0

s = - \frac{1}{4} + i \frac{3}{4}, s = - \frac{1}{4} - i \frac{3}{4}

Solution steps

4 s^{2} + 2 s + 1 = 0

Solve with the quadratic formula

s_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 4 \cdot 1}{2 \cdot 4}

Simplify

2^{2} - 4 \cdot 4 \cdot 1 : 23 i

s_{1, 2} = \frac{- 2 \pm 2 3 i}{2 \cdot 4}

Separate the solutions

s_{1} = \frac{- 2 + 2 3 i}{2 \cdot 4}, s_{2} = \frac{- 2 - 2 3 i}{2 \cdot 4}

s = \frac{- 2 + 2 3 i}{2 \cdot 4} : - \frac{1}{4} + i \frac{3}{4}

s = \frac{- 2 - 2 3 i}{2 \cdot 4} : - \frac{1}{4} - i \frac{3}{4}

The solutions to the quadratic equation are:

s = - \frac{1}{4} + i \frac{3}{4}, s = - \frac{1}{4} - i \frac{3}{4}

y^{2} = 42

m^{2} + 2 m - 35 = 0

- 8 x^{2} + 7 x - 6 = 0

y, y^{3} = 2 x^{2}

- \frac{1}{2} x^{2} = 20 - 6 x

What are the solutions to the equation 4s^2+2s+1=0 ?
The solutions to the equation 4s^2+2s+1=0 are s=-1/4+i(sqrt(3))/4 ,s=-1/4-i(sqrt(3))/4
Find the zeros of 4s^2+2s+1=0
The zeros of 4s^2+2s+1=0 are s=-1/4+i(sqrt(3))/4 ,s=-1/4-i(sqrt(3))/4