What are the solutions to the equation -x^2+280x-17600=0 ?

The solutions to the equation -x^2+280x-17600=0 are x=20(7-sqrt(5)),x=20(7+sqrt(5))

Find the zeros of -x^2+280x-17600=0

The zeros of -x^2+280x-17600=0 are x=20(7-sqrt(5)),x=20(7+sqrt(5))

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- x^{2} + 280 x - 17600 = 0

x = 20 (7 - 5), x = 20 (7 + 5)

Decimal Notation

x = 95.27864 \dots, x = 184.72135 \dots

Solution steps

- x^{2} + 280 x - 17600 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 280 \pm 28 0 ^{2} - 4 ( - 1 ) ( - 17600 )}{2 ( - 1 )}

28 0^{2} - 4 (- 1) (- 17600) = 405

x_{1, 2} = \frac{- 280 \pm 40 5}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 280 + 40 5}{2 ( - 1 )}, x_{2} = \frac{- 280 - 40 5}{2 ( - 1 )}

x = \frac{- 280 + 40 5}{2 ( - 1 )} : 20 (7 - 5)

x = \frac{- 280 - 40 5}{2 ( - 1 )} : 20 (7 + 5)

The solutions to the quadratic equation are:

x = 20 (7 - 5), x = 20 (7 + 5)

3 p^{2} + p - 9 = - 2

x^{2} - 8 + 15 = 0

8 - 6 x + x^{2} = 0

8 + 14 t - 15 t^{2} = 0

- 7 x^{2} + 28 = 0

What are the solutions to the equation -x^2+280x-17600=0 ?
The solutions to the equation -x^2+280x-17600=0 are x=20(7-sqrt(5)),x=20(7+sqrt(5))
Find the zeros of -x^2+280x-17600=0
The zeros of -x^2+280x-17600=0 are x=20(7-sqrt(5)),x=20(7+sqrt(5))