What are the solutions to the equation (x+5)^2+127=6 ?

The solutions to the equation (x+5)^2+127=6 are x=11i-5,x=-11i-5

Find the zeros of (x+5)^2+127=6

The zeros of (x+5)^2+127=6 are x=11i-5,x=-11i-5

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(x + 5)^{2} + 127 = 6

x = 11 i - 5, x = - 11 i - 5

Solution steps

(x + 5)^{2} + 127 = 6

Move

127

to the right side

(x + 5)^{2} = - 121

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 5 = - 121 : x = 11 i - 5

Solve

x + 5 = - - 121 : x = - 11 i - 5

The solutions to the quadratic equation are:

x = 11 i - 5, x = - 11 i - 5

4 (x^{2} - 5) + 5 = - 3

7 x^{2} - 19 x - 6 = 0

4 x^{2} - 5 x = 6

s^{2} + 1.2 s + 1

a, a^{2} - 3 a y^{2} + 3 y^{4} - b = 0

What are the solutions to the equation (x+5)^2+127=6 ?
The solutions to the equation (x+5)^2+127=6 are x=11i-5,x=-11i-5
Find the zeros of (x+5)^2+127=6
The zeros of (x+5)^2+127=6 are x=11i-5,x=-11i-5